Как преобразовать HTML url в RTF файл на C# и .NET
Полный код
GitHubusing System;
using System.IO;
using SautinSoft;
namespace Sample
{
class Test
{
static void Main(string[] args)
{
// Get your free 30-day key here:
// https://sautinsoft.com/start-for-free/
// Convert HTML url to RTF file.
// If you need more information about "HTML to RTF .Net"
// Email us at: [email protected].
ConvertHtmlUrlToRtfFile();
}
public static void ConvertHtmlUrlToRtfFile()
{
SautinSoft.HtmlToRtf h = new SautinSoft.HtmlToRtf();
string inpFile = @"https://www.sautinsoft.net/samples/utf-8.html";
string outFile = "Result.rtf";
// Specify the 'BaseURL' property that component can find the full path to images, like a: <img src="..\pict.png" and
// to external css, like a: <link rel="stylesheet" href="/css/style.css">.
HtmlConvertOptions opt = new HtmlConvertOptions();
opt.BaseURL = @"https://www.sautinsoft.net/samples/utf-8.html";
if (h.Convert(inpFile, outFile, opt))
{
// Open the result for demonstration purposes.
System.Diagnostics.Process.Start(new System.Diagnostics.ProcessStartInfo(outFile) { UseShellExecute = true });
}
}
}
}
Imports System
Imports System.IO
Imports SautinSoft
Namespace Sample
Friend Class Test
Shared Sub Main(ByVal args() As String)
' Get your free 30-day key here:
' https://sautinsoft.com/start-for-free/
' Convert HTML url to RTF file.
' If you need more information about "HTML to RTF .Net"
' Email us at: [email protected].
ConvertHtmlUrlToRtfFile()
End Sub
Public Shared Sub ConvertHtmlUrlToRtfFile()
Dim h As New SautinSoft.HtmlToRtf()
Dim inpFile As String = "https://www.sautinsoft.net/samples/utf-8.html"
Dim outFile As String = "Result.rtf"
' Specify the 'BaseURL' property that component can find the full path to images, like a: <img src="..\pict.png" and
' to external css, like a: <link rel="stylesheet" href="/css/style.css">.
Dim opt As New HtmlConvertOptions()
opt.BaseURL = "https://www.sautinsoft.net/samples/utf-8.html"
If h.Convert(inpFile, outFile, opt) Then
' Open the result for demonstration purposes.
System.Diagnostics.Process.Start(New System.Diagnostics.ProcessStartInfo(outFile) With {.UseShellExecute = True})
End If
End Sub
End Class
End Namespace
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